For 2 x 2 Matrices
A = [ 2 -3 ] where A = [ a b ]
[ 2 1 ] [ c d ]
Find the inverse of matrix A.
Solution:
A-1 = 1/(ad-bc) [ d -b ]
[ -c a ]
= 1/(2 + 6) [ 1 3 ]
[-2 2 ]
= 1/8 [ 1 3 ]
[-2 2 ]
A-1 = [ 1/8 3/8 ]
[-1/4 1/4 ]
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